- 23 Sections
- 117 Lessons
- 22 Weeks
Expand all sectionsCollapse all sections
- 21 Coulomb’s Law15
- 1.1Introduction4 Minutes
- 1.2Section 21.1 Coulomb’s Law26 Minutes
- 1.3POLARIZATION (Induced Charge)9 Minutes
- 1.41. Insulators: 2. Conductors:12 Minutes
- 1.5Charging By Induction8 Minutes
- 1.6Coulomb’s Law27 Minutes
- 1.7Mutiple Forces18 Minutes
- 1.8Example 213 Minutes
- 1.9Example 38 Minutes
- 1.10Example 418 Minutes
- 1.11Extra Home Practice 118 Minutes
- 1.12Extra Home Practice 28 Minutes
- 1.13Section 21.2 Charge is Quantized20 Minutes
- 1.14Section 21.3 Charge is Conserved12 Minutes
- 1.15Homework Ch 2145 Minutes
- 22 Electric Fields7
- 23 Gauss’ Law5
- 24 Electric Potential11
- 4.1The electric potential & electric potential energy I26 Minutes
- 4.2The electric potential & electric potential energy II19 Minutes
- 4.324.1 Electric Potential14 Minutes
- 4.5Work-Energy Conservation21 Minutes
- 4.6Section 24.2 Equipotential Surfaces and the Electric Field28 Minutes
- 4.7Potential Difference vs. Travel Along Path in Electric Field14 Minutes
- 4.8Section 24.3 Potential due to a Charged Particle21 Minutes
- 4.9Section 24.6 Calculating the Field from the Potential28 Minutes
- 4.10Section 24.7 Electric Potential Energy of a System of Charged Particles10 Minutes
- 4.11Section 24.8 Potential of Charged Isolated Conductor12 Minutes
- 4.12مراجعة لايف ليلة اختبار الميجر53 Minutes
- 25 Capacitance9
- 5.1• 25.1 Capacitance19 Minutes
- 5.2Charging a Capacitor23 Minutes
- 5.3Section 25.3 Capacitors in Parallel and In Series14 Minutes
- 5.4Extra Practice17 Minutes
- 5.5Section 25.4 Energy Stored in an Electric Field16 Minutes
- 5.6Example 5 & Example 623 Minutes
- 5.7Section 25.5 Capacitor with a Dielectric18 Minutes
- 5.8Example 7 & Example 87 Minutes
- 5.9Dielectric In a Parallel Plate Capacitor ( same potential difference)11 Minutes
- 26 Current and Resistance0
- 27 Circuits0
- 28 Magnetic Fields0
- 29 Magnetic Fields Due to Currents0
- 30 Induction and Inductance0
- 34 Images0
- Chapter 19 (Electric Charges, Forces, and Fields)14
- 12.1Part 1. (19.1 Electric Charge)27 Minutes
- 12.2Part 2. (• POLARIZATION (Induced Charge))20 Minutes
- 12.3Coulomb’s law16 Minutes
- 12.4Superposition of forces26 Minutes
- 12.5Coulomb’s law. Practice33 Minutes
- 12.619.4 The Electric Field39 Minutes
- 12.719.4 The Electric Field. P231 Minutes
- 12.819.5 Electric Field Lines24 Minutes
- 12.919.6 Shielding and Charging by Induction20 Minutes
- 12.1019.7 Electric Flux and Gauss’s Law23 Minutes
- 12.11Ch 19 revision Part 131 Minutes
- 12.12Ch 19 revision Part 232 Minutes
- 12.13Homework ch 1954 Minutes
- 12.14quiz 130 Minutes
- Ch 20: Electric potential and Electric potential Energy.9
- 13.120.1 Electric Potential Energy and Electric Potential28 Minutes
- 13.220.2 Energy Conservation44 Minutes
- 13.320.3 Electric Potential of Point Charges33 Minutes
- 13.420.4 Equipotential Surfaces and The Electric Field33 Minutes
- 13.520.5 Capacitors and Dielectrics35 Minutes
- 13.6Ch 20 revision Part 129 Minutes
- 13.7Ch 20 revision Part 254 Minutes
- 13.8Ch 20 revision Part 331 Minutes
- 13.9Homework ch 2041 Minutes
- Ch 21: Electric Current and Direct Current Circuits.13
- 14.121.1 Electric Current20 Minutes
- 14.221.2 Resistance and Ohm’s Law26 Minutes
- 14.321.3 Energy and Power in Electric Circuits16 Minutes
- 14.421.4 Resistors in Series and Parallel39 Minutes
- 14.5(C) Combination Circuit24 Minutes
- 14.6Combination Circuit. Practice26 Minutes
- 14.7(D) Kirchhoff’s Rules49 Minutes
- 14.821.6 Circuits Containing Capacitors25 Minutes
- 14.9Exercise 65, page 84918 Minutes
- 14.1021.7 RC Circuits50 Minutes
- 14.11حل مسائل اضافية من الكتاب38 Minutes
- 14.12Revision quiz ch 2179 Minutes
- 14.13Homework ch 21
- Ch 22: Magnetism.10
- 15.122.1 Magnetic Field17 Minutes
- 15.222.2 The Magnetic Force on Moving Charges14 Minutes
- 15.3Magnetic force right hand rule12 Minutes
- 15.422.4 THE MAGNETIC FORCE EXERTED ON A CURRENT-CARRYING WIRE19 Minutes
- 15.522.6 Electric Currents, Magnetic Fields, and Ampère’s Law22 Minutes
- 15.6Example 6, Active example 2,12 Minutes
- 15.7C) Forces between current carrying wires15 Minutes
- 15.8حل مسائل اضافية من الكتاب44 Minutes
- 15.9Ch 22: Magnetism. (Homework)23 Minutes
- 15.10quiz14 Minutes
- Ch 23: Magnetic Flux and Faraday's4
- Ch 24: Alternating Current Circuits.0
- Ch 26: Geometrical Optics.4
- 1 st major6
- 19.1second semester Thursday February 20, 202549 Minutes
- 19.2first semester term 241 Thursday, October 24, 202476 Minutes
- 19.3First semester term 232 Thursday, March 6, 202459 Minutes
- 19.4First semester term 231 Thursday, October 26, 202373 Minutes
- 19.5second Semester Term 222 Wednesday, March 15, 202349 Minutes
- 19.6first Semester term 221 Tuesday October 18, 202263 Minutes
- Finial Exam6
- 20.1phys 205. Finial term 241 (Dec. 16, 2024)105 Minutes
- 20.2Phys 205 Finial term 232 (june.3,2024)103 Minutes
- 20.3Phys 205 Finial. 231 (December 26, 2023)98 Minutes
- 20.4Phys 205 Finial. 221. (December 27, 2022)105 Minutes
- 20.5phys 205 finial 202 (Monday 26/4/2021)94 Minutes
- 20.6phys 205 finial 191 (Dec. 23,2019)70 Minutes
- Paractice1
- Lab3
- دعواتي للجميع بالتفوق و النجاح0
Section 21.1 Coulomb’s Law
If you bring two charged glass rods close together and they repel each other, what can you conclude about them?
A. Both rods have the same sign of charge.
B. The rods have opposite signs of charge.
C. One rod is charged and the other is neutral.
D. Both rods are conductors.
When an amber rod is rubbed with fur, what is the primary mechanism that causes the rod to become negatively charged?
A. The fur induces a temporary negative charge on the rod without any transfer of particles.
B. The rubbing process creates new electrons on the surface of the amber rod.
C. Electrons are transferred from the fur to the amber rod.
D. Positive charges (protons) are transferred from the amber rod to the fur.
what happens to the total mass of the amber rod and fur system after they are rubbed together?
A. The mass of the rod increases, and the mass of the fur decreases by the same amount.
B. The mass of the rod increases, while the mass of the fur stays the same.
C. The mass of both the rod and the fur remains unchanged because electrons are massless.
D. The total mass of the system decreases because energy is converted to charge.